If the angle of elevating of a tower from a distance of 100 meters from its foot is 60. The height of tower will be(Assistant CPD PPSC 2022)

Let AB be the tower and a point P at a distance of 100 m from its foot, the angle of elevation of the top of the tower is 60° Let the height of the tower = h Then in right ΔABPtanθ=PerpendicularBase=ABPB⇒tan60∘=h100⇒3–√=h100⇒h=1003–√∴Heightoftower=1003–√